8x=0.6x^2

Solution for 8x=0.6x^2 equation:

8x=0.6x^2

We move all terms to the left:

8x-(0.6x^2)=0

We get rid of parentheses

-0.6x^2+8x=0

a = -0.6; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-0.6)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-0.6}=\frac{-16}{-1.2}
=13+0.4/1.2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-0.6}=\frac{0}{-1.2}
=0
$